Respuesta :

Answer:

[tex]45P2 = 45*44=1980[/tex]

Step-by-step explanation:

Previous concepts

A permutation, "also called an arrangement number, is a rearrangement of the elements of an ordered list S into a one-to-one correspondence with S itself. The number of permutations on a set of n elements is given by n! factorial".

The formula for permutation is given by:

[tex]nPx =\frac{n!}{(n-x)!}[/tex]

Solution to the problem

We are interested in find 45P2, if we use the last formula we got this:

[tex]45P2 = \frac{45!}{(45-2)!}=\frac{45!}{43!}[/tex]

Now we can use the following property for the factorial operation:

[tex]n! = n (n-1)![/tex]

So using this two times we can rewrite the expression 45! on this way:

[tex]45! = 45* 44![/tex]

[tex]45! = 45*44* 43! [/tex]

And replacing this we got:

[tex]45P2 = \frac{45!}{(45-2)!}=\frac{45*44*43!}{43!}[/tex]

We can cancel the 43! of the numerator with the 43! of the denominator and we got:

[tex]45P2 = 45*44=1980[/tex]

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