Answer:
[tex]45P2 = 45*44=1980[/tex]
Step-by-step explanation:
Previous concepts
A permutation, "also called an arrangement number, is a rearrangement of the elements of an ordered list S into a one-to-one correspondence with S itself. The number of permutations on a set of n elements is given by n! factorial".
The formula for permutation is given by:
[tex]nPx =\frac{n!}{(n-x)!}[/tex]
Solution to the problem
We are interested in find 45P2, if we use the last formula we got this:
[tex]45P2 = \frac{45!}{(45-2)!}=\frac{45!}{43!}[/tex]
Now we can use the following property for the factorial operation:
[tex]n! = n (n-1)![/tex]
So using this two times we can rewrite the expression 45! on this way:
[tex]45! = 45* 44![/tex]
[tex]45! = 45*44* 43! [/tex]
And replacing this we got:
[tex]45P2 = \frac{45!}{(45-2)!}=\frac{45*44*43!}{43!}[/tex]
We can cancel the 43! of the numerator with the 43! of the denominator and we got:
[tex]45P2 = 45*44=1980[/tex]