Answer:
13.3 g
Explanation:
Let's consider the following reaction.
3 H₂SO₄ + 2 Fe → Fe₂(SO₄)₃ + 3 H₂
The molar mass of H₂SO₄ is 98.1 g/mol. The moles of H₂SO₄ in 35.0 g are:
35.0 g × (1 mol / 98.1 g) = 0.357 mol
The molar ratio of H₂SO₄ to Fe is 3:2. The moles of Fe are:
0.357 mol H₂SO₄ × (2 mol Fe/ 3 mol H₂SO₄) = 0.238 mol
The molar mass of Fe is 55.8 g/mol. The mass of Fe is:
0.238 mol × (55.8 g/mol) = 13.3 g
