Answer:
Explanation:
height, h = 125 miles = 125 x 1609 m = 201125 m = 0.2 x 10^6 m
Rdaius, R = 2.44 x 10^6 m
Mass, M = 3.3 x 10^23 kg
Let vo be the orbital speed.
The formula for the orbital speed is given by
[tex]v_{o}=\sqrt{\frac{GM}{R+h}}[/tex]
where, M is the mass of mercury, R be the radius of mercury
[tex]v_{o}=\sqrt{\frac{6.67\times10^{-11}\3.3\times 10^{23}}{2.64\times 10^{6}}[/tex]
vo = 2887.47 m/s
Time period, T = 2Ï€(R+h) / vo
T = 2 x 3.14 x 2.64 x 10^6 / 2887.47
T = 5741.77 seconds
T = 1.6 hours