Respuesta :

Step-by-step explanation:

we have

∠CAX=∠BAX

AC=AB

[AX] a common side for both triangles ΔACX and ΔABX

then

ΔACX and ΔABX are two isometric triangles

therefore XC=XB

then the triangle  ΔXBC is isoceles

then ∠XBC ≡ ∠XCB.

:)

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