Respuesta :
Answer: 0.3264
Step-by-step explanation:
Let Andy's variable = a
Bob's variables = b
Andy mean score Ma = 150
Andy standard deviation SDa = 30
Bob mean score Mb = 165
Bob standard deviation = 15
Therefore, the probability of Andy having greater score than Bob
= P( a-b > 0)
The mean X(a-b) = Ma - Mb
X(a-b)= 150 - 165 = -15
Standard deviation = sqrt Variance
Variance = 30² + 15² = 1125
SD = sqrt (1125) = 33.54
Therefore, the
P(a-b > 0) = 1 - P(a-b <0)
P(a-b<0) = P(z, 0-(-15)/33.54 )
P(a-b <0) = P (z, 0.45) = 0.6736
Since
P(a-b > 0) = 1 - P(a-b <0)
P(a-b> 0) = 1 - 0.6736 = 0.3264
Therefore, Andy has the probability of 0.3264 of scoring greater Bob
Andy has the probability of 0.3264 scoring greater than Bob.
Let Andy's variable = a
Bob's variables = b
Andy mean score Ma = 150
Andy standard deviation SDa = 30
Bob mean score Mb = 165
Bob standard deviation = 15
Therefore, the probability of Andy having greater score than Bob
= P( a-b > 0)
The mean X(a-b) = Ma - Mb
X(a-b)= 150 - 165 = -15
Standard deviation = sqrt Variance
Variance = 30² + 15² = 1125
SD = sqrt (1125) = 33.54
Therefore, P(a-b > 0) = 1 - P(a-b <0)
P(a-b<0) = P(z, 0-(-15)/33.54 )
P(a-b <0) = P (z, 0.45) = 0.6736
Since, P(a-b > 0) = 1 - P(a-b <0)
P(a-b> 0) = 1 - 0.6736 = 0.3264
Therefore, Andy has the probability of 0.3264 of scoring greater than Bob.
For more information:
https://brainly.com/question/14116780