Answer:
The mass of NaOH that is required is 150 g
Explanation:
We calculate the weight of 1 mol of NaOH
Weight Na =23g/mol, Weight H= 1g/mol, Weight 0= 16g/mol
Weight NaOH =( 23+1 + 16) g/mol = 40 g/mol
1 dm3 (1000ml or 1 liter)---1 ,5 mol
2,5 dm3-------------------------x= (2,5dm3x 1,5mol)/ 1 dm3= 3, 75 mol
1mol NaOH----40 g
3, 75mol NaOH--x= (3, 75mol NaOHx40g)/1 mol NaOH= 150g
