Which equation describes this line

Answer:
y-10=2(x-1)
Step-by-step explanation:
eq. of a line through (x1,y1) and (x2,y2) is
[tex]y-2=\frac{10-2}{1+3}(x+3)\\or~y-2=2(x+3)\\or~ y-10=\frac{2-10}{-3-1}(x-1) \\or~y-10=2(x-1)[/tex]
Answer:
y - 10 = 2(x - 1).
Step-by-step explanation:
The slope of the line = (10-2)/(1 - -3)
= 8/4
= 2.
Using the point (-3, 2) and the point-slope form of the straight line;
Y - Y1 = M(X - X1) we have
y - 2 = 2(x - -3)
y - 2 = 2(x + 3)
This is not one of the choices so we use the other point (1,10)
y - 10 = 2(x - 1).
Note that the 2 equations are the same - if we write them in a different form we get y = 2x + 8 in each case.