Answer:
The wavelength of the light is 562.5 nm
Solution:
As per the question:
Order, n = 1
Slit separation, d = [tex]2.5\times 10^{- 6}\ m[/tex]
Distance from the bright fringe, y = 0.18 m
Distance between the screen and the grating, D = 0.8 m
Now,
We know from the eqn for diffraction:
[tex]n\lambda = dsin\theta[/tex]
n = 1
[tex]\lambda = dsin\theta[/tex] (1)
Also,
For very small angle, [tex]\theta[/tex]:
[tex]sin\theta[/tex] ≈ [tex]tan\theta = \frac{y}{D} = \frac{0.18}{0.8} = 0.225[/tex]
Using the above value in eqn (1):
[tex]\lambda = 2.5\times 10^{- 6}\times 0.225 = 5.625\times 10^{- 7}\ m = 562.5\ nm[/tex]