Question

A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation y = 0.011 cos(6t) where y is the displacement in meters and the time t is in seconds.

(a) What is the amplitude of the wave, in meters?
(b) What is the frequency of the wave, in hertz?
(c) What is the wavelength of the wave, in meters?

Answer 1

Answer:

a)A= 0.011 m

b)f= 0.954 Hz

c)λ= 6.28 m

Explanation:

u= 6 m/s

y = 0.011 cos(6t)

Standard form  

Y=A cosωt

A=Amplitude

ω=Angular frequency

By comparing

A= 0.011 m

ω = 6 rad/s

We know that

ω = 2 π f

6 = 2 π f

f= 0.954 Hz

We know that

u =  f λ

λ=Wavelength ,u=speed

6 = 0.954 x λ

λ= 6.28 m