Question

A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 15 minutes. Air traffic control approved a new flight plan that
will allow her to arrive two times faster than she calculated in her original flight plan. Let x represent the time, in minutes, of her original flight. Create an equation
that can be used to predict the number of minutes after 4:00 pm she will arrive at her destination.
y = 2x + 15
©y=-*x+15
y = x-15
y = 2x - 15

Answer 1

Answer:

$y = \frac{x}{2}+15$ will be the equation that can be used to predict the number of minutes after 4:00 pm she will arrive at her destination.

Step-by-step explanation:

Let x represent the time, in minutes, of her original flight plan.

Let y represents the time, in minutes, of her new flight plan.

The time of Original flight schedule = 4:00 pm

The number of minutes delayed by Original flight = 15 minutes

As the new flight plan is two times faster than original flight plan.

So, the equation of new flight plan will be:                    

                                  $y = \frac{1}{2}x$

                                  $y = \frac{x}{2}$

But, the original flight plan was delayed by 15 minutes. Hence, the equation to predict the number of minutes after 4:00 pm she will arrive at her destination will become:

                                  $y = \frac{x}{2}+15$

So, $y = \frac{x}{2}+15$ will be the equation that can be used to predict the number of minutes after 4:00 pm she will arrive at her destination.

                                             

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Answer 2

Answer:

B

Step-by-step explanation:

y represents the time she will get there. She will get there in 1/2 the time so 1/2x.   >>  y=1/2x

BUT she was delayed for 15 minutes before she departed with her alternate route. So you have to add 15 minutes.  >>  y=1/2x+15