Question

A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has determined that home delivery will be successful if the average time spent on the deliveries does not exceed 35 minutes. The owner has randomly selected 20 customers and has delivered pizzas to their homes in order to test if the mean delivery time actually exceeds 35 minutes. Suppose the P-value for the test was found to be 0.0295. State the correct conclusion.

Answer 1

Answer:

At α=0.05, we reject the null hypothesis since 0.0295<0.05

At α=0.02, we fail to reject the null hypothesis since  0.0295>0.02

At α=0.03, we reject the null hypothesis since  0.0295<0.03

At α=0.025, we fail to reject the null hypothesis since  0.0295>0.025

Step-by-step explanation:

Let p be the time spent during pizza deliveries. Then

$H_{0}$: p=35 min

$H_{a}$: p>35 min

p-value of the test is 0.0295.

To draw a conclusion, we must assume several significance levels and state the significance by comparing p-value against the significance level.

If p-value is smaller than the significance level, then we can reject the null hypothesis in favor of alternative hypothesis. If not, we fail to reject the null hypothesis.