The rate of jet in still air is 880 mph and rate of wind is 180 mph
Given that Flying against the wind, a jet travels 2100 miles in 3 hours
Flying with the wind, the same jet travels 8480 miles in 8 hours
To find: rate of the jet in still air and rate of the wind
Let the rate of jet in still air be "x" miles per hour and rate of wind be "y" miles per hour.
against wind speed = x - y mph
with wind speed = x + y mph
We know that,
[tex]speed = \frac{distance}{time}[/tex]
[tex]\text{against wind speed }=\frac{2100}{3}=700 \mathrm{mph}[/tex]
[tex]\text{with wind speed} =\frac{8480}{8}=1060 \text{ mph}[/tex]
Hence we get,
x - y = 700 --- eqn 1
x + y = 1060 --- eqn 2
Add the above two equations,
x - y + x + y = 700 + 1060
2x = 1760
From eqn 1 we get,
880 - y = 700
y = 880 - 700 = 180
Thus the rate of jet in still air is 880 mph and rate of wind is 180 mph