Answer:
Consider the following explanation
Explanation:
We will use derivative to get minimum cost.
To get minimum cost, we will solve C'(x) =0 for x.
C(x)=0.1x2-20x+12942
C'(x)=0.2x-20
C'(x)=0 => x= 100 ( Critical point)
Now apply second derivative test to decide minimum value of C(x).
C"(x)=0.2
At x=100, C"(x) = 0.2 >0 . Hence C(x) will be minimum when x=100.
So Cmin = 0.1(100)2-20(100) + 12942.
Cmin = 11942