Answer:
The shape of the sampling distribution for the sample proportion is going to be normal with mean [tex]\mu = 0.42[/tex] and [tex]\sigma = \sqrt{\frac{0.42*0.58}{300}} = 0.0285[/tex].
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\frac{\sigma}{\sqrt{n}}[/tex]
So the shape of the sampling distribution for the sample proportion is going to be normal with mean [tex]\mu = 0.42[/tex] and [tex]\sigma = \sqrt{\frac{0.42*0.58}{300}} = 0.0285[/tex].