Answer:
There are 20 DVD's in Louis's collection.
Step-by-step explanation:
Given:
Jake owns twice as many DVDs as Louis.
Bo has sixty fewer DVDs than five times Louis's collection.
Now, to find the DVD's in Louis's collection if Jake and Bo have the same amount of DVDs.
As per given :
Let the collection of Louis DVD's be [tex]x[/tex].
Let the collection of Jake DVD's be [tex]2x[/tex].
And the collection of Bo DVD's be [tex]5x-60[/tex].
According to question:
Jake collection = Bo collection.
[tex]2x=5x-60.[/tex]
Adding both sides by 60 we get:
⇒ [tex]2x+60=5x.[/tex]
Subtracting both sides by [tex]2x[/tex] we get:
⇒ [tex]60=3x.[/tex]
Dividing both sides by 3 we get:
⇒ [tex]20=x.[/tex]
⇒ [tex]x=20.[/tex]
Therefore, there are 20 DVD's in Louis's collection.
