Step-by-step explanation:
A rectangular lot whose perimeter is 260 ft is fenced along three sides. An expensive fencing along the lot's length cost $ 18per foot. An inexpensive fencing along the two side widths costs only $ 3per foot.
So we have
l + 2 w = 260 -------------------eqn 1
And total cost is 1800 $
That is
18 l + 2 x 3 w = 1800
3l + w = 300 -------------------eqn 2
eqn 2 x 2
6l + 2w = 600 -------------------eqn 3
eqn 3 - eqn 1
6l + 2w - l - 2w = 600 - 260
5l = 340
l = 68 ft
Substituting in eqn 1
68 + 2 w = 260
2w = 192
w = 96 ft
Lot's dimension is 68 ft x 96 ft