Question

What is the area of a trapezoid with height 14xy^2 cm, a base with length 3x^2 cm, and another base length 7x^2 cm?

Answer 1

Answer:

$\therefore \textrm{Area of Trapezoid }= 70x^{3}y^{2}\ cm^{2}$

Step-by-step explanation:

Given:

Shape is of Trapezoid

Height = 14xy² cm

Length 1 = 3x² cm ( one Parallel side)

Length 2 = 7x² cm ( other Parallel side)

To Find:

Area of Trapezoid = ?

Solution:

We know that

$\textrm{Area of Trapezoid }= 0.5(length\ 1+length\ 2)Height$

substituting the given values we get

$\textrm{Area of Trapezoid }= 0.5\times(3x^{2}+7x^{2})\times 14xy^{2}$

$\textrm{Area of Trapezoid }= (10x^{2})7xy^{2}$..((x^{a}x^{b}=x^{(a+b)})

$\therefore \textrm{Area of Trapezoid }= 70x^{3}y^{2}\ cm^{2}$