Respuesta :
Answer:
r=6.05km/hr
z=59.1 degree to the horizontal
Explanation:
A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place
can be solved using pythagoras theorem
r^2=o^2+a^2
r^2=5.2^2+3.1^2
r^2=36.65
r=6.1km/hr is te birds velocity relative to the ground
tanz=5.2/3.1
z=tan^-1(5,2/3.1)
z=59.1 degree to the horizontal
Answer:
6.0 km/hr
Explanation:
The wind's velocity relative to the ground is perpendicular to the bird's velocity relative to the air.
When you use Pythagorean theorem to add the two velocity vectors, we find that the bird's velocity relative to the ground is
6.0 kilometers/hour southeast.