Answer:
When the diver dives to a depth where the pressure is 1.16 atm, he has 1006.1 mL of air in his lungs.
Explanation:
Step 1: Data given
Volume in his lungs = 1159.49 mL
The pressure = 764.96 mmHg = 764.96 / 760 = 1.00652646 atm
When he dives the pressure changes to 1.16 atm.
Step 2: Calculate final volule
(P1*V1)/T1 = (P2*V2)/T2
⇒ Since the temperature will be constant we can simplify as:
P1*V1 = P2*V2
⇒ with P1 = The initial pressure 1.00652646 atm
⇒ with V1 = The initial volume = 1159.49 mL
⇒ with P2 = The pressure after diving = 1.16 atm
⇒ with V2 = The volume of air in his lungs after diving
V2 = (P1*V1)/P2
V2 =(1.00652646 * 1159.49)/1.16
V2 = 1006.1 mL
When the diver dives to a depth where the pressure is 1.16 atm, he has 1006.1 mL of air in his lungs.
