Answer:
t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]
Explanation:
First, we need to arrange the problem to work in the same unit system (SI).
We need to convert the 1800 [miles] to meters, therefore:
[tex]1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km][/tex]
Now using the following equation of kinematics, for the avarage velocity we have:
[tex]v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\[/tex]
therefore:
[tex]t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s][/tex]
Now we can convert from seconds into days.
[tex]193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\ t = 2.2[days][/tex]
Now if the truck has the need to come back, the team will spend double time.
t= 4.4 [days]