Option B
When you roll two number cubes, the odds in simplest form against getting two numbers greater than 3 is 1 : 4
Solution:
The probability of an event is given as:
[tex]\text {probability of an event }=\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}[/tex]
Given that,
Tow number cubes are rolled
To find: Probability of getting two numbers greater than 3
On a number cube there are 6 numbers {1, 2, 3, 4, 5, 6} Out of which 3 numbers are greater than 3 {4, 5, 6}
So, total number of possible outcomes = 6
Favourable outcomes = number greater than 3 = 3
When you roll one number cube, probability of getting number greater than 3:
[tex]\text { Probability (number greater than } 3 \text { ) }=\frac{3}{6}[/tex]
When you roll two number cubes, probabilty is given as:
[tex]\text { Probability (number greater than }3)= \frac{3}{6} \times \frac{3}{6}=\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}[/tex]
[tex]Probability = \frac{1}{4}[/tex]
In ratio form we can write as 1 : 4
Option B is correct
