Answer:
Therefore the area of Composite figure is 44 unit².
Step-by-step explanation:
Consider the composite Figure as
One Trapezoid and Two Triangles
One Square box = 1 unit
Dimension for Trapezoid:
Parallel Base Sides , i.e a= 3 units and b = 5 units
Height = 3+5 = 8 Units
Dimension for Both the Triangle is same :
Base = 4 units
Height = 3 units
To Find:
Area of the Composite Figure = ?
Solution:
For Composite Figure
[tex]\textrm{Area of the Composite Figure}=\textrm{Area of the Trapezoid}+\textrm{Area Of Two Triangles}[/tex]........( 1 )
Now For Trapezoid we have
[tex]\textrm{Area of the Trapezoid} =0.5\times \textrm{Sum of Parallel sides}\times Height[/tex]
Substituting the given values we get
[tex]\textrm{Area of the Trapezoid} =0.5\times (a+b)\times Height=0.5(8)(8)=32[/tex]
Now for Triangle we have
[tex]\textrm{Area of the Triangle} =0.5\times Base\times Height[/tex]
Substituting the given values we get
[tex]\textrm{Area of the Triangle} =0.5\times 4\times 3=6[/tex]
Therefore Area of anther Triangle will be also SAME i.e 6
Therefore Substituting Area trapezoid and triangle in equation ( 1 ) we get
[tex]\textrm{Area of the Composite Figure}=32+ 6+ 6=32+12=44\ unit^{2}[/tex]
Therefore the area of Composite figure is 44 unit².