Question

A JIT system uses kanban cards to authorize movement of incoming parts. In one portion of the system, a work center uses an average of 100 parts per hour while running. The manager has assigned an inefficiency factor of .20 to the center. Standard containers are designed to hold six dozen parts each. The cycle time for parts containers is about 105 minutes. How many containers are needed?

Answer 1

Answer:

3 containers

Explanation:

The number of containers would be

= Annual demand × time × (1 + inefficiency factor) ÷ holding pieces

= 100 parts × 1.75 × (1 + 0.20) ÷ 72

= 2.917 containers

The time is converted from minutes to hour i.e 105 minutes ÷ 60 minutes = 1.75

The holding piece would be

= 6 dozen × 12

= 72

1 dozen have 12 pieces

We take all the items which are given in the question. As all the things are needed for the computation part