Question

Small-plane pilots regularly compete in "message drop" competitions, dropping heavy weights (for which air resistance can be ignored) from their low-flying planes and scoring points for having the weights land close to a target. A plane 65 m above the ground is flying directly toward a target at 46 m/s .
A.) At what distance from the target should the pilot drop the weight?B.) The pilot looks down at the weight after she drops it. Where is the plane located at the instant the weight hits the ground?not yet over the targetpast the targetdirectly over the targetnot enough information to determine

Answer 1

Answer:

a)165,6 m

b)Directly over the target

Explanation:

a)To calculate the time that ball hits the ground after released, we will use the free fall formula below:

$h=(1/2)*g*t^2$

h=65m

g=9,8m/s^2

$65=0,5*9,8*t^2\\t^2=65/(0,5*9,8)\\t=3,6 sec$

Plane has the speed of 46m/s. Due to there is no air resistance weight remains the same speed while free falling. So the distance will be:

$x=46*3,6=165,6 m$

b) Due to no air resistance plane and weight will be at the same speed on the air. Therefore, when the weight hits the ground plane will be directly over the target.