Answer:
The answer to your question is letter A) cot x
Step-by-step explanation:
[tex]\frac{1 - cot x}{tan x - 1}[/tex]
Remember that cot x = [tex]\frac{1}{tan x}[/tex]
Then
[tex]\frac{1 - \frac{1}{tan x} }{tanx -1}[/tex]
Simplify
[tex]\frac{\frac{tan x - 1}{tan x} }{tan x - 1}[/tex]
[tex]\frac{tan x - 1}{tan x (tan x - 1)}[/tex]
[tex]\frac{1}{tan x}[/tex]
Result
[tex]\frac{1}{tan x} = cot x[/tex]