Question

(Score for Question 1: ___ of 5 points)

1. In a candy shop, jellybeans which sell for $2.50 a pound are mixed with skittles which sell for $4 a pound to form a jellybean-skittles mix that sells for $3.50 a pound. How much of each are used to make 30 pounds of the mixture?


(a) Write a system of linear equations that models this situation.

(b) Use the substitution or elimination method to solve for how many pounds of jellybeans and how many pounds of skittles are used to make the 30-pound mixture.

Hint:

Equation one will represent that jellybeans and skittles will equal a total amount of pounds.

Equation 2 will represent that cost of each individual component (added together) equal the total cost of a 30-pound mixture.

Answer:

(Score for Question 2: ___ of 5 points)

2. Sam and Kevin both worked hard over the summer. Together they earned a total of $425. Kevin earned $25 more than Sam.

(a) Write a system of equations for the situation. Use s for the amount Sam earned and k for the amount Kevin earned.

(b) Solve the system of equations.

Answer:

3. (Score for Question 3: ___ of 5 points)

Solve the system of equations by substitution.


6 = −4x + y

−5x − y = 21


Answer:


Solve the system by the elimination method.


2x + y = 20

6x – 5y = 12


Answer:


please help me immediately please!!! whoever answers this gets marked brainliest

Answer 1

Answer:

The separated values of x and y from the given equation is $x=\frac{13-3y}{4}, y=1-\frac{4}{13}x$

Step-by-step explanation:

Given equation is $4 x+3y=13$

Now to find the separated values of x and y with the given equation.

Now find the value of x and so we have to separate the value x from the given equation

$4x+3y=13$

$4x=13=3y$

$x=\frac{13-3y}{4}$

Therfore $x=\frac{13-3y}{4}$

Now find the value of y and so we have to separate the value y from the given equation

$4x+13y=13$

$13y=13-4x$

$y=\frac{13-4x}{13}$

$y=\frac{13}{13}-\frac{4x}{13}$

$y=1-\frac{4}{13}$

Therefore $y=1\frac{4}{13}x$

The separated values of x and y from the given equation is

$x=\frac{13-3y}{4}, y=1-\frac{4}{13}x$