Question

identify the vertex for
f(x)=4x^2-8x-4

Answer 1

Answer:

Step-by-step explanation:

You could complete the square to do this, or you could just evaluate the h coordinate using the simple formula

$h=-\frac{b}{2a}$

then find k by subbing that h value into the equation for x to find y which is the same as k.  In our quadratic, a = 4, b = -8, and c = -4.

$h=\frac{-(-8)}{2(4)}=1$

Now sub that value into the quadratic to find y (k):

$4(1)^2-8(1)-4=4-8-4=-8$

The vertex of the quadratic is (1, -8)