Kelli weighs 425 N, and she is sitting on a playground swing that hangs 0.36 m above the ground. Her mom pulls the swing back and releases it when the seat is 1.00 m above the ground. Assume that air resistance is negligible. (a) How fast is Kelli moving when the swing passes through its lowest position?

Respuesta :

Answer:

V = 3.54 m/s

Explanation:

Using the conservation of energy:

[tex]E_i = E_f[/tex]

so:

[tex]wh = \frac{1}{2}mV^2[/tex]

where w is te weigh of kelly, h the distance that kelly decends, m is the mass of kelly and V the velocity in the lowest position.

So, the mass of kelly is:

m = 425N/9.8 = 43.36 Kg

and h is:

h = 1m-0.36m =0.64m

then, replacing values, we get:

[tex](425N)(0.64m) = \frac{1}{2}(43.36kg)v^2[/tex]

Solving for v:

V = 3.54 m/s

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