Answer:
The answer to your question is letter C
Explanation:
Data
Volume = 2 L
Molarity = 0.100 M
Molecular weight Na₂CO₃ = (2 x 23) + (1 x 12) + (3 x 16)
= 46 + 12 + 48
= 106 g
Process
1.- Calculate the grams of Na₂CO₃ needed
106 g ---------------- 1 mol
x ---------------- 0.1 moles
x = (0.1 x 106) / 1
x = 10.6 g
2.- Calculate the grams of Na₂CO₃ needed for 2 liters of solution
10.6 g -------------- 1 liter
x -------------- 2 liters
x = (10.6 x 2) / 1
x = 21.2 grams of Na₂CO₃