Question

The electric field of a sinusoidal electromagnetic wave obeys the equation E=?(375V/m)sin[(5.97×1015rad/s)t+(1.99×107rad/m)x] .Part B:What is the amplitude of the magnetic field of this wave?Part CWhat is the frequency of the wave?B = ?T

Answer 1

Answer:

Explanation:

The equation of electric field is

E = 375 Sin(5.97 x 10^15 t + 1.99 x 10^7 x)

Compare with the standard equation

E = Eo Sin(ωt + kx)

(b) Amplitude of electric field, Eo = 375 V/m

Amplitude of magnetic field, Bo = Eo / c = 375 / (3 x 10^8)

Bo = 125 x 10^-8 Tesla

Bo = 1.25 x 10^-6 Tesla

(c) ω = 5.97 x 10^15 rad

2 x 3.14 x f = 5.97 x 10^15

f = 0.95 x 10^15 Hz

f = 9.5 x 10^14 Hz