Question

let this be an easy 5 points for your brainly account all is ask for in return is a "thank you"



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Answer 1

Answer:

The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is 14 neutrons

Explanation:

Symbol of Si isotope

$_{14}^{28}\textrm{Si}$

Number of Neutron = Mass number - Atomic Number

Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu

Atomic Number = Total number of Protons present in the nucleus.

Si = 14

Number of neutron = 24 - 14

                                = 14