Speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour
Let s = the speed of the boat in still water in miles/hour
Let c = the speed of the current in miles/hour
Formula to remember:
If the speed of a boat in still water is s miles/hr and the speed of the current is c miles/hr, then:
Speed downstream = (s + c) miles per hour
Speed upstream = (s - c) miles per hour
Given:
boat traveled 153 miles downstream and back
distance for downstream = 153 miles
distance for upstream = 153 miles
time taken for downstream = 9 hours
Time taken for upstream = 17 hours
The relation between speed, distance and time is given as:
[tex]distance = speed \times time[/tex]
For downstream:
[tex]153 = (s + c) \times 9[/tex]
[tex]s + c = \frac{153}{9} = 17[/tex]
s + c = 17 ------- eqn 1
For upstream:
[tex]153 = (s - c) \times 17\\\\s - c = \frac{153}{17} = 9[/tex]
s - c = 9 ------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "s" and "c"
Add eqn 1 and eqn 2
s + c = 17
s - c = 9
(+) -------------
2s = 26
Substitute s = 13 in eqn 1
13 + c = 17
c = 17 - 13 = 4
Thus the speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour