Question

|x| + 4 > 7 plz help and hurry

Answer 1

Answer:

The solution is $(-\infty,-3)\cup(3,\infty)$.

Step-by-step explanation:

Given:

The inequality given is:

$|x|+4>7$

In order to simplify for 'x', we first isolate 'x' on one side.

Adding -4 on both sides, we get:

$|x|+4-4>7-4\\\\|x|>3$

Now, $|x|$ is an absolute value function which is defined as:

$|x|=\left \{ {{-x}\ \ x<0 \atop {x\ \ x\geq0}} \right.$

Therefore, the given inequality can be rewritten as:

$-x > 3\\x<-3$ and $x > 3$

Therefore, the solution is $(-\infty,-3)\cup(3,\infty)$.