Answer:
(a) $13116.51
(b) $1315.03
(c) $12762.81
Explanation:
We have given principal amount P = $10000
Rate of interest r = 5.5 %
Time = 5 years
(a) When compounded semiannually
Rate of interest [tex]=\frac{5.5}{2}=2.75[/tex] %
Time period n= 5×2=10 period
So amount after 5 year
[tex]A=P(1+\frac{r}{100})^n=10000\times (1+\frac{2.75}{100})^{10}=$13116.51[/tex]
(b) When compounded monthly
Rate of interest [tex]=\frac{5.5}{12}=0.4583[/tex] %
Time period n= 5×12=60 period
So amount after 5 year
[tex]A=P(1+\frac{r}{100})^n=10000\times (1+\frac{0.4583}{100})^{60}=$13157.03[/tex]
(c) When compounded continuously
Rate of interest = 5.5 %
Time period n= 5 year
So amount after 5 year
[tex]A=P(1+\frac{r}{100})^n=10000\times (1+\frac{5}{100})^{5}=$12762.81[/tex]