Question

An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8,000 g and an area of 5.00 cm2 and is free to slide up and down, keeping the pressure of the gas constant.
a. How much work is done on the gas as the temperature of 0.280 mol of the gas is raised from 15.0 degrees C to 27.0 degrees C?
b. What does the sign of your answer to part (a) indicate?
A. The surroundings do positive work on the gas.
B. The gas does positive work on its surroundings.
C. There is no work done by the gas of the surroundings.

Answer 1

Answer:

Explanation:

Given

mass of gas $m=8000 gm=8 kg$

Area of Piston $A=5 cm^2$

$T_1=15^{\circ}C$

$T_2=27^{\circ}C$

no of moles $n=0.28$

Work done on the gas is given by

$W=-P\Delta V$

$P\Delta V$ can also be written as $nR\Delta T$

as PV=nRT

$W=-nR\Delta T$

$W=-0.28\times 8.314\times (27-15)$

$W=-27.93 J$

negative sign indicates that work is done on the system i.e. surrounding done a positive work on the gas