In Drosophila, an autosomal gene determines the shape of the hair, with B giving straight and b giving bent hairs. On another autosome, there is a gene of which a dominant allele I inhibits hair formation so that the fly is hairless (i has no known phenotypic effect). a. If a straight-haired fly from a pure line is crossed with a fly from a pure-breeding hairless line known to be an inhibited bent genotype, what will the genotypes and phenotypes of the

F1

and the

F2

be? b. What cross would give the ratio 4 hairless : 3 straight : 1 bent?

All the offspring will be hairless since there is one dominant I allele which will inhibit hair production regardless of the type of allele of other gene.

Two F1 flies will be crossed to obtain F2 flies. IiBb X IiBb :

I_B_ : hairless = 9

I_bb : hairless = 3

iiB_ : straight hair = 3

iibb : bent hair = 1

Hairless : straight : bent will be in 12 : 3 : 1 ratio.

b. The offspring of this cross :

hairless : I_ _ _

straight : iiB_

bent : iibb

There is a bent offspring which has both the recessive alleles of both the genes. Hence it must have obtained the two alleles from the two parents. So their genotype is _i_b and _i_b.

Half of the offspring are hairless as given by the ratio. This is only possible if the cross is between Ii and ii fly:

I i

i Ii ii

So the genotype is Ii_b and ii_b.

The remaining hairy flies are in 3:1 ratio of straight to bent. This is only possible if the cross is between Bb and Bb fly:

B b

B BB Bb

b Bb bb

So the final genotype of the flies is IiBb and iiBb.