Question

In Drosophila, normal eyes are brick red in color. Homozygotes for recessive alleles at the brownlocus (bw/bw) have brown eyes. Homozygotes for recessive alleles at the cinnabar locus (cn/cn) have bright red eyes. The two genes interact: bw/bw; cn/cn have white eyes. If a pure-breeding brown is crossed to a pure-breeding cinnabar fly, color eyes will the F1 have and what proportion of the F2 will be white?

A.brown, 3/16

B.brick red, 9/16

C.bright red, 3/16

D.brick red, 1/16

E.answers not shown in those given here.

Answer 1

Answer:

answer is d

Explanation:

THe answer is D because this is dihybrid cross and we cross bwbw RR( normal red eye gene) x RR cncn. The F1 progeny has R in all locus of these genes so all will be R as heterozygous. When F1 progeny crossed, the 1/4 of bw cross and 1/4 of cn cross habe bwbw/cncn and will be white. So it will be 1/4x1/4 = 1/16