Use the graph below to answer the following question: If slope is calculated using the equation, "m = (y2-y1) / (x2-x1)," what is the slope of the secant line? Be sure to include all math work and units in your final answer.
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slope = (45 - 0) / (6 - 0)
slope = 45/6
slope = 7.5
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Answer : The slope of the secant line is, 7.5 cm/s
Explanation :
Formula used :
[tex]m=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]
Here,
[tex]x_1,x_2[/tex] are coordinates of time and [tex]y_1,y_2[/tex] are coordinates of position.
[tex](x_1,y_1)=(0,0)[/tex] and [tex](x_2,y_2)=(6,45)[/tex]
[tex]m=\frac{(45-0)cm}{(6-0)s}[/tex]
[tex]m=7.5cm/s[/tex]
Thus, the slope of the secant line is, 7.5 cm/s