Use the graph below to answer the following question: If slope is calculated using the equation, "m = (y2-y1) / (x2-x1)," what is the slope of the secant line? Be sure to include all math work and units in your final answer.

Use the graph below to answer the following question If slope is calculated using the equation m y2y1 x2x1 what is the slope of the secant line Be sure to inclu class=

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slope = (45 - 0) / (6 - 0)

slope = 45/6

slope = 7.5

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Answer : The slope of the secant line is, 7.5 cm/s

Explanation :

Formula used :

[tex]m=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

Here,

[tex]x_1,x_2[/tex] are coordinates of time and [tex]y_1,y_2[/tex] are coordinates of position.

[tex](x_1,y_1)=(0,0)[/tex] and [tex](x_2,y_2)=(6,45)[/tex]

[tex]m=\frac{(45-0)cm}{(6-0)s}[/tex]

[tex]m=7.5cm/s[/tex]

Thus, the slope of the secant line is, 7.5 cm/s

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