Answer:
B) The frequency will increase
Explanation:
The length of the instrument is given by
[tex]L=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2L[/tex]
Wavelength is given by
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\dfrac{v}{f}=2L\ or\ L\propto \dfrac{1}{f}[/tex]
It can be seen that the length is inversely proportional to the frequency.
Here, the length of the trombone is decreasing so the frequency will increase.