Respuesta :
Answer:
[tex]\angle{A}=53.1^{\circ}[/tex]
[tex]\angle{A}=80.9^{\circ}[/tex]
[tex]b=12.4[/tex]
Step-by-step explanation:
Please find that attachment.
We have been given that in ΔABC, ∠C measures 46° and the values of a and c are 10 and 9, respectively.
First of all, we will find measure of angle A using Law Of Sines:
[tex]\frac{\text{sin(A)}}{a}=\frac{\text{sin(B)}}{b}=\frac{\text{sin(C)}}{c}[/tex], where, A, B and C are angles corresponding to sides a, b and c respectively.
[tex]\frac{\text{sin(A)}}{10}=\frac{\text{sin(46)}}{9}[/tex]
[tex]\frac{\text{sin(A)}}{10}=\frac{0.719339800339}{9}[/tex]
[tex]\frac{\text{sin(A)}}{10}=0.0799266444821111[/tex]
[tex]\frac{\text{sin(A)}}{10}*10=0.0799266444821111*10[/tex]
[tex]\text{sin(A)}=0.799266444821111[/tex]
Upon taking inverse sine:
[tex]A=\text{sin}^{-1}(0.799266444821111)[/tex]
[tex]A=53.060109978759^{\circ}[/tex]
[tex]A\approx 53.1^{\circ}[/tex]
Therefore, the measure of angle A is 53.1 degrees.
Now, we will use angle sum property to find measure of angle B as:
[tex]m\angle{A}+m\angle{B}+m\angle{C}=180^{\circ}[/tex]
[tex]53.1^{\circ}+m\angle{B}+46^{\circ}=180^{\circ}[/tex]
[tex]m\angle{B}+99.1^{\circ}=180^{\circ}[/tex]
[tex]m\angle{B}+99.1^{\circ}-99.1^{\circ}=180^{\circ}-99.1^{\circ}[/tex]
[tex]m\angle{B}=80.9^{\circ}[/tex]
Therefore, the measure of angle B is 80.9 degrees.
Now, we will use Law Of Cosines to find the length of side b.
[tex]b^2=a^2+c^2-2ac\cdot\text{cos}(B)[/tex]
Upon substituting our given values, we will get:
[tex]b^2=10^2+9^2-2(10)(9)\cdot\text{cos}(80.9^{\circ})[/tex]
[tex]b^2=100+81-180\cdot 0.158158067254[/tex]
[tex]b^2=181-28.46845210572[/tex]
[tex]b^2=152.53154789428[/tex]
Upon take square root of both sides, we get:
[tex]b=\sqrt{152.53154789428}[/tex]
[tex]b=12.3503663060769173[/tex]
[tex]b\approx 12.4[/tex]
Therefore, the length of side b is approximately 2.4 units.
![Ver imagen ApusApus](https://us-static.z-dn.net/files/d99/fee9da3a00856980153d077ee0c3e702.png)
Answer:
∠A = 53.1°, ∠B = 80.9°, b = 12.4
Step-by-step explanation:
i got it right on my test