Explanation:
Sodium has atomic number of 11 and its electronic configuration is given by:
[tex][Na]=1s^22s^22p^63s^1[/tex]
The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.
[tex]Na\rightarrow Na^++1e^-[/tex]
[tex][Na^+]=1s^22s^22p^63s^0[/tex]
Sodium has single valency that is 1.
Let nbe the valency of the ion 'X'
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
[tex]Na_nX_1[/tex]
So, the formulas for all the possible compounds that sodium can form with the other ions will be:
[tex]Na_nX_1[/tex]