Respuesta :

Answer:

The Area of square pyramid is 36 + 36[tex]\sqrt{5}[/tex] .

Step-by-step explanation:

Given as :

For A square pyramid

The measure of each base side = b = 6 feet

The height of the pyramid = h = 6 feet

Let The Total area of pyramid = A square feet

Now, According to question

The area of square pyramid

Area = b² + 2 × b [tex]\sqrt{\frac{b^{2} }{4}+h^{2}  }[/tex]

Where b is the square base edge

And h is the pyramid height

I.e A = 6² + 2 × 6 [tex]\sqrt{\frac{6^{2} }{4}+6^{2}  }[/tex]

Or, A = 36 + 12 × [tex]\sqrt{\frac{36 }{4}+36  }[/tex]

Or, A = 36 + 12 × [tex]\sqrt{9+36}[/tex]

Or, A = 36 + 12 × [tex]\sqrt{45}[/tex]

Or, A = 36 + 12 × 3[tex]\sqrt{5}[/tex]

Or, A = 36 + 36[tex]\sqrt{5}[/tex]

So,The Area of square pyramid = A = 36 + 36[tex]\sqrt{5}[/tex]

Hence, The Area of square pyramid is 36 + 36[tex]\sqrt{5}[/tex] . Answer

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