Answer:
The Area of square pyramid is 36 + 36[tex]\sqrt{5}[/tex] .
Step-by-step explanation:
Given as :
For A square pyramid
The measure of each base side = b = 6 feet
The height of the pyramid = h = 6 feet
Let The Total area of pyramid = A square feet
Now, According to question
The area of square pyramid
Area = b² + 2 × b [tex]\sqrt{\frac{b^{2} }{4}+h^{2} }[/tex]
Where b is the square base edge
And h is the pyramid height
I.e A = 6² + 2 × 6 [tex]\sqrt{\frac{6^{2} }{4}+6^{2} }[/tex]
Or, A = 36 + 12 × [tex]\sqrt{\frac{36 }{4}+36 }[/tex]
Or, A = 36 + 12 × [tex]\sqrt{9+36}[/tex]
Or, A = 36 + 12 × [tex]\sqrt{45}[/tex]
Or, A = 36 + 12 × 3[tex]\sqrt{5}[/tex]
Or, A = 36 + 36[tex]\sqrt{5}[/tex]
So,The Area of square pyramid = A = 36 + 36[tex]\sqrt{5}[/tex]
Hence, The Area of square pyramid is 36 + 36[tex]\sqrt{5}[/tex] . Answer