Answer:
1) A
2) C
3) B
4) A
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6) Incomplete information(picture missing)
7) Incomplete information(picture missing)
8) A
9) C
10) C
Explanation:
1) m = 15kg, a = [tex]10ms^{-2}[/tex], F = ma = 15*10 = 150N
2) m = 3kg, v = [tex]4ms^{-1}[/tex], r = 4m, F = [tex]\frac{mv^{2} }{r}[/tex]
[tex]\frac{3*4^{2} }{4}[/tex] = 12N
3) a = [tex]10ms^{-2}[/tex], r = 10m, v=?
F = [tex]\frac{mv^{2} }{r}[/tex] and F = ma
equating the two equations and cancelling a, we have:
[tex]\frac{v^{2} }{r}[/tex] = a
making v the subject of formula, we have:
v = [tex]\sqrt{ar}[/tex]
= [tex]\sqrt{100}[/tex]
= 10[tex]ms^{-1}[/tex]
4) r = 10m, v = [tex]5ms^{-1}[/tex], a = ?
F = [tex]\frac{mv^{2} }{r}[/tex]
F = ma
equating the above equations and making a subject of formula, we get:
a = [tex]\frac{v^{2} }{r}[/tex]
a = 25/10 = 2.5[tex]ms^{-2}[/tex]
5) I can't find the picture associated with this question
6) I can't find the picture associated with this question
7) I can't find the picture associated with this question
8) F = [tex]\frac{mv^{2} }{r}[/tex]
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F = [tex]v^{2}[/tex]
Now, if v is tripled
F = [tex](3v)^{2}[/tex]
F = 9[tex]v^{2}[/tex]
We can see that the force will be 9X greater than it was.
9) F = [tex]\frac{mv^{2} }{r}[/tex]
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F = [tex]v^{2}[/tex]
Now, if v is doubled
F = [tex](2v)^{2}[/tex]
F = 4[tex]v^{2}[/tex]
We can see that the force will be 4X greater than it was.
10) F = [tex]\frac{mv^{2} }{r}[/tex]
assuming m and v is unity, that is the values are 1 respectively
F = 1/r
if r is doubled,
F = 1/2 * 1/r
We can see that the force is 1/2 as big as it was
