Answer:
maximum profit = $7500
so correct option is c $7500
Explanation:
given data
mean = 500
standard deviation = 300
cost = $10
price = $25
Inventory salvaged = $5
to find out
What is its maximum profit
solution
we get here maximum profit that is express as
maximum profit = mean × ( price - cost ) ..................................1
put here value in equation 1 we get maximum profit
maximum profit = mean × ( price - cost )
maximum profit = 500 × ( $25 - $10 )
maximum profit = 500 × $15
maximum profit = $7500
so correct option is c $7500