Answer:
(a) 164.5 kJ.
(b) 122.5 kJ
Explanation:
Specific Heat Capacity: The specific heat capacity of a substance, is the quantity of heat required to raise the temperature of a unit mass (1 kg) of a substance through a degree rise in temperature (1 K). It is expressed in J/kgK
Mathematically, it can be expressed as
Q = cmΔT.
Where Q = quantity of heat, c = specific heat capacity, m = mass of the substance, ΔT = change in temperature
(a) Q = cmΔT
Where c = specific heat capacity of the body = 3.5 kJ/kgK = 3500 J/kgK, m = 1.0 kg,
ΔT = T₂ - T₁ = 37-(-10) = 37+10 = 47 °C
Substituting this values in the equation above,
Q = 3500×1.0×47
Q = 164500 J
Q = 164.5 kJ.
Therefore, Energy absorbed by the body = 164.5 kJ
(b) Q =cmΔT
Where Q = quantity of heat, c = specific heat capacity of the the body = 3.5 kJ/kgK = 3500 J/kgK, m = 1.0 kg,
ΔT = T₂ - T₁ = 37 -2 = 35 °C.
∴ Q = 3500×1.0×35
Q = 122500 J
Q = 122.5 kJ
∴ Energy absorbed by the body = 122.5 kJ
