Question

The path of a model rocket can be represented by the equation h(t) = - t ^ 2 + 20t + 12 where h(t) is the height , in feet of the rocket at any given time, t. What is the height of the model rocket after 3 seconds from launch?

Answer 1

Answer:

The height of the rocket after 3 seconds is 63 feet.

Step-by-step explanation:

The path of a model rocket is represented by:

$h(t)=-t^2+20t+12$

where $h(t)$ represents the height in feet of rocket and $t$ represents time in seconds.

To find the height of the model rocket after 3 seconds from launch.

Solution:

In order to find the  height of the model rocket after 3 seconds from launch, we will plugin $t=3$ in the given function of path of rocket.

Thus, we have

$h(3)=-(3)^2+20(3)+12$

$h(3)=-9+60+12$

$h(3)=63$

Thus, height of the rocket after 3 seconds is 63 feet.