Question

Brent has a shopping bag with 8 similar size containers of yogurt: 2 strawberry, 3 cherry, and 3 raspberry. If he randomly takes 2 yogurt containers from the bag
without replacement, what is the probability that neither will be strawberry yogurt?

Answer 1

Answer:$\frac{15}{28}$

Step-by-step explanation:

Number of strawberry = 2

Number of cherry = 3

Number of  = 3

Total number = 8

Brent randomly takes 2 yogurt containers from the bag

without replacement ,we are to find the probability that hat neither will be strawberry yogurt.

Let r represent  raspberry and c represents  Cherry ,then Bent selection could be :

{ rr , cc , rc , cr}

Calculating this , we have

($\frac{3}{8}$ x  $\frac{2}{7}$ ) + ($\frac{3}{8}$ x  $\frac{2}{7}$ ) + ($\frac{3}{8}$ x  $\frac{3}{7}$ ) + ($\frac{3}{8}$ x  $\frac{3}{7}$ )

= $\frac{30}{56}$

= 15/28

Therefore , the probability that neither will be strawberry yogurt= 15/28