Answer:
The principal amount invested is $4395.93 .
Step-by-step explanation:
Given as :
The Amount that saved for future = A = $5,000
The bank applied rate of interest = r = 4.3% compounded monthly
The time period of loan = t = 3 years
Let the principal amount invested = $p
Now, From monthly Compound Interest method
Amount = principal × [tex](1+\dfrac{\textrm rate}{12\times 100})^{12\times time}[/tex]
Or, A = p × [tex](1+\dfrac{\textrm r}{12\times 100})^{12\times t}[/tex]
Or, $5000 = p × [tex](1+\dfrac{\textrm 4.3}{12\times 100})^{12\times 3}[/tex]
Or, $5000 = p × [tex](1.003583)^{36}[/tex]
Or, $5000 = p × 1.137414
∴ p = [tex]\dfrac{5000}{1.137414}[/tex]
i.e p = $4395.93
So, The principal amount invested = p = $4395.93
Hence, The principal amount invested is $4395.93 . Answer