Answer: The rate of boat is 60 kmh.
The rate of current is 5 kmh.
Step-by-step explanation:
Alright, lets get started.
Suppose the rate of boat in still water is : b kmh
Suppose the rate of current is : c kmh
When the boat is going upstream, the relative speed will be : [tex](b-c)[/tex]
When the boat is going downstream, the relative speed will be: [tex](b+c)[/tex]
Boat travels 220 kilometers in 4 hours going upstream.
[tex]speed=\frac{distance}{time}[/tex]
[tex](b-c)=\frac{220}{4}[/tex] .................. equation (1)
It travels 260 kilometers going downstream in the same amount of time.
[tex](b+c)=\frac{260}{4}[/tex] ................... equation (2)
Adding equation 1 and 2
[tex]b-c+b+c=\frac{220}{4}+\frac{260}{4}[/tex]
[tex]2b=\frac{480}{4}[/tex]
[tex]2b=120[/tex]
[tex]b=60[/tex]
Plugging the value of b as 60 in equation 2
[tex]60+c=\frac{260}{4}[/tex]
[tex]60+c=65[/tex]
[tex]c=5[/tex]
Hence the rate of boat is 60 kmh.
Hence the rate of current is 5 kmh.
Hope it will help :)