Answer: 7 dots
Explanation:
Fluorine and neon have seven and eight dots, respectively: With the next element, sodium, the process starts over with a single electron because sodium has a single electron in its highest-numbered shell, the n = 3 shell.
7 dots would be placed around fluorine in a Lewis electron dot diagram.
In Lewis structure, we represent valence electrons by dots and bonds by line.
Atomic number of fluorine is 9. Electronic configuration is 2,7. So 7 valence electrons are present in fluorine.
7 dots would be placed around fluorine in a Lewis electron dot diagram. Some features of Lewis dot diagram are,
Thus, we can conclude that, 7 electrons are present in the valence shell of fluorine. Therefore, 7 dots would be placed around fluorine in a Lewis electron dot diagram.
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